2y^2-5x+8y-4=0

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Solution for 2y^2-5x+8y-4=0 equation:


Simplifying
2y2 + -5x + 8y + -4 = 0

Reorder the terms:
-4 + -5x + 8y + 2y2 = 0

Solving
-4 + -5x + 8y + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + -5x + 8y + 4 + 2y2 = 0 + 4

Reorder the terms:
-4 + 4 + -5x + 8y + 2y2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -5x + 8y + 2y2 = 0 + 4
-5x + 8y + 2y2 = 0 + 4

Combine like terms: 0 + 4 = 4
-5x + 8y + 2y2 = 4

Add '-8y' to each side of the equation.
-5x + 8y + -8y + 2y2 = 4 + -8y

Combine like terms: 8y + -8y = 0
-5x + 0 + 2y2 = 4 + -8y
-5x + 2y2 = 4 + -8y

Add '-2y2' to each side of the equation.
-5x + 2y2 + -2y2 = 4 + -8y + -2y2

Combine like terms: 2y2 + -2y2 = 0
-5x + 0 = 4 + -8y + -2y2
-5x = 4 + -8y + -2y2

Divide each side by '-5'.
x = -0.8 + 1.6y + 0.4y2

Simplifying
x = -0.8 + 1.6y + 0.4y2

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